(1)*($x^{2}$-1)*($x^{2}$+2x-5)
(7c-2)*(7c-2)
x(x+1)(x+2)
(2x+2)*(x+5)*($3x^{2}$-4x-15)
log(y,27)=3+1/log(8,y)
ă xă^4+ 16+ ă4xă^2 en x^2+ 2x
(7c-2)x(7c-2)
6+4 $\sqrt{\Box}$ 2
(5r+7)tan(47)=137.2
\frac{x}{5}-\frac{3x-2}{4}=\frac{1}{3}
