How many numbers not exceeding 10000 can be made using the digits

2,4,5,6,8 if repetition of digits is allowed?

Answer = :

8000 = 2^6 * 5^3

X = 2^a * 3^b * 5^c

The highest common factor of 8000 and X is 2 * 5^3.

The lowest common multiple of 8000 a...

Place each of the digits 1, 2, 5, 7, 8, 9, in a different box to make this multiplication equation

true.

6 111 × 3 = 1 0 114

$($a^{-1}$+$b^{-1}$ )^{m/n}$

x^{\log _{10}\left(\sqrt{x}\right)}=100

what is the answer parallel to the line 2y-x=1 passing through (-2,0)

1+1

show the working of 1002 divided by 60

x^5 - 3*x^4 - 4*x^3 + 28*x^2 - 37*x + 15

$\frac{1}{a}$ + $\frac{2}{a+2}$