2x+0.6=3x
a car travels 100km in due west and then 120 kmdue 50 degree east of north whats the car resultsng displacement
abc + bac + cba
= (8^10 + 9 - (-1)^10)/6
= (8^8 + 9 - (-1)^8)/6
= (8^7 + 9 - (-1)^7)/6
= (8^4 + 9 - (-1)^4)/6
= (8^5 + 9 - (-1)^5)/6
= (8^3 + 9 - (-1)^3)/6
= (8^2 + 9 - (-1)^2)/6
