850*4+425
2,5=x.0,4
d/du (2u^2)
√8
3 +√32
5 −36∶(−4)+(−9)1 =
(x + 3)^2 + (y - 4)^2 = 16
show that the curve r(1-cos) = 2a p^2 varies as r^3
Solve the recurrence relation 3𝑎𝑛+1 − 4𝑎𝑛 = 0, 𝑛 ≥ 0, 𝑎1 = 5
If 𝑢=(𝑥2+𝑦2+𝑧2)−1
2 , prove that 𝜕2𝑢
𝜕𝑥2
+𝜕2𝑢
𝜕𝑦2
𝜕𝑧2
=0
((26,6 + j0,85) x j10) / 26,67 + j11,86
