If 𝑢=(𝑥2+𝑦2+𝑧2)−1

2 , prove that 𝜕2𝑢

𝜕𝑥2

+𝜕2𝑢

𝜕𝑦2

+𝜕2𝑢

𝜕𝑧2

=0

asked by guest
on Nov 25, 2024 at 6:44 am



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