(x + 3)^2 + (y - 4)^2 = 16
You asked:
Investigate the equation: \({\left( x + 3 \right)}^{2} + {\left( y - 4 \right)}^{2} = 16\).
MathBot Answer:
The graph of the equation \({\left( x + 3 \right)}^{2} + {\left( y - 4 \right)}^{2} = 16\) is a circle.
The coordinates of its center are \(\left(-3, 4\right)\).
Its radius is \(4\).
The cirlce has parameterization: \[\begin{aligned}x\left(\theta\right) &= -3 + 4 \cos{\left(\theta \right)}\\y\left(\theta\right) &= 4 + 4 \sin{\left(\theta \right)}\end{aligned}\]