137( 5)
=
solve\:for\:a,\:b,\:c,\:d\:\begin{pmatrix}a+b&a+c\\ \:b+c&b-d\end{pmatrix}=\begin{pmatrix}2d-c&-c\\ \:4&a\end{pmatrix}
0=$2x^{5}$- $5x^{4}$+ $2x^{3}$+ $2x^{2}$ +x-1
0=$2x^{5}$- $5x^{4}$+ $2x^{3}$+ $2^{2}$ +x-1
1 The distance x of a runner from a fixed point is measured (in metres) at intervals of half a
second. The data obtained are
t 0...
y= 2(x-2)^2 + 2
how to solve for y
under root 3 to the power minus 2
4x/3 + 3x/4
Subscript[P, 1] Subscript[V, 1]/Subscript[T, 1]= Subscript[P, 2]Subscript[V, 2]/Subscript[T, 2];
a-b=
-4-5
