0=2x52x^{5}- 5x45x^{4}+ 2x32x^{3}+ 222^{2} +x-1

asked by guest
on Jan 24, 2025 at 4:55 pm



You asked:

Solve the equation 0=2x5−5x4+2x3+22+x−10 = 2 {x}^{5} - 5 {x}^{4} + 2 {x}^{3} + {2}^{2} + x - 1 for the variable xx.

MathBot Answer:

The 5 solutions to the equation are: x≈−0.70579427x=−0.0409668384690714−0.876115855488098i≈−0.040966838−0.87611586ix=−0.0409668384690714+0.876115855488098i≈−0.040966838+0.87611586ix=1.64386397177214−0.245887821361785i≈1.643864−0.24588782ix=1.64386397177214+0.245887821361785i≈1.643864+0.24588782i\begin{aligned}x &\approx -0.70579427\\x &= -0.0409668384690714 - 0.876115855488098 i \approx -0.040966838 -0.87611586 i\\x &= -0.0409668384690714 + 0.876115855488098 i \approx -0.040966838 + 0.87611586 i\\x &= 1.64386397177214 - 0.245887821361785 i \approx 1.643864 -0.24588782 i\\x &= 1.64386397177214 + 0.245887821361785 i \approx 1.643864 + 0.24588782 i\end{aligned}

Solutions were approximated using numerical methods.

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