solve\:for\:a,\:b,\:c,\:d\:\begin{pmatrix}a+b&a+c\\ \:b+c&b-d\end{pmatrix}=\begin{pmatrix}2d-c&-c\\ \:4&a\end{pmatrix}
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
solve\:for\:a,\:b,\:c,\:d\:\begin{pmatrix}a+b&a+c\\ \:b+c&b-d\end{pmatrix}=\begin{pmatrix}2d-c&-c\\ \:4&a\end{pmatrix}
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.