18,529,103,315,599,360 x 2 =
7 divide 2 and 1 fifth
cos(x) = 1,x
10m+6=7m+21
volume ofcell
3a^2sin60×c
find the next two terms of the sequence
-1, 2, 12,40
4h+3 = 6h - 15
20 $a^{2}$ -54a+35
9,264,551,657,799,680 x 2 =
3.14 X 48
