Math Problem Solver

\[ 4\frac{3}{4} + 5\frac{1}{4} + 7 = 17 \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{4}{1}\), \(\frac{3}{4}\), \(\frac{5}{1}\), \(\frac{1}{4}\), and \(\frac{7}{1}\) is \(4\). \[ \begin{aligned} 4\frac{3}{4} + 5\frac{1}{4} + 7 &= \frac{4 \cdot 4}{1 \cdot 4} + \frac{3 \cdot 1}{4 \cdot 1} + \frac{5 \cdot 4}{1 \cdot 4} + \frac{1 \cdot 1}{4 \cdot 1} + \frac{7 \cdot 4}{1 \cdot 4} \\ &= \frac{16 + 3 + 20 + 1 + 28}{4} \\ &= \frac{68}{4} \\&= 17 \end{aligned} \]