0,6+7

asked by guest
on Jan 22, 2025 at 11:07 am



MathBot Answer:

The sum of \(0\) and \(6 + 7\) is:

\[\begin{aligned}&=\left(0\right) + \left(6 + 7\right) \\\\ &= 6 + 7 \\\\ &= 13 \\\\\end{aligned}\]


The difference of \(0\) and \(6 + 7\) is:

\[\begin{aligned}&=\left(0\right) - \left(6 + 7\right) \\\\ &= -13 \\\\\end{aligned}\]


The product of \(0\) and \(6 + 7\) is:

\[\begin{aligned}&=\left(0\right) \cdot \left(6 + 7\right) \\\\ &= 0 \\\\\end{aligned}\]


The quotient of \(0\) and \(6 + 7\) is:

\[\begin{aligned}&= \frac{\left(0\right)}{\left(6 + 7\right)} \\\\ &= 0 \\\\\end{aligned}\]