(93+6x)/(14+x)=7
(93+7x)/(14+x)=7
(3x+6x) × 3x + 9x⁴÷3x²
13/2 + 17/4
Y=x^2+8x+15
Square A and Square B are both $2009$ by $2009$ squares. Square A has both its length and width increased by an amount $x$, while ...
10x^2
\lim _{x\to \infty }\left(\frac{\sqrt{x^2+1}}{3x+2}\right)
B = 2M - 5C2 make C the subject of the equation
8x³:4
