Y=x^2+8x+15
You asked:
Investigate the equation: \(Y = {x}^{2} + 8 x + 15\).
MathBot Answer:
The graph of the equation \(Y = {x}^{2} + 8 x + 15\) is a parabola.
The coordinates of its vertex are: \(\left(-1, -4\right)\)
The coordinates of its focus are: \(\left(- \frac{3}{4}, -4\right)\)
The directrix has equation: \(4 Y + 5 = 0\).
The parabola has parameterization: \[\begin{aligned}Y\left(\theta\right) &= -1 + \theta^{2}\\x\left(\theta\right) &= -4 + \theta\end{aligned}\]