\lim _{x\to \infty }\left(\frac{\sqrt{x^2+1}}{3x+2}\right)
You asked:
Evaluate the expression: \(\lim_{x \to \infty}{\frac{\sqrt{{x}^{2} + 1}}{3 x + 2}}\)
MathBot Answer:
\[\lim_{x \to \infty}{\frac{\sqrt{{x}^{2} + 1}}{3 x + 2}} = \frac{1}{3}\]