y-1=1(x-(-1)) in standard form
3(X+8)=2(X+2)+10X
$\frac{x+3}{x^2+3x-4}$ = $\frac{x+2}{x^2-16}$
18/24
Substitute y= 4x +7 into the equation y+ 3x + 8, to find the value of x
homogeneous differential equation:
dy/dx = x^2 + xy / y^2 + xy
1.4212001e+12
3(X+2)=5-2(X-3)
9/3+2(9+10)-8+4X3
$\frac{\120,56}{\8}$
