-3+(0*1+2)-2(-2)*(4-4)+1-(1)

asked by guest
on Apr 06, 2025 at 1:37 pm



You asked:

Evaluate the expression: −3+0⋅1+2−2⋅−2(4−4)+1−1-3 + 0 \cdot 1 + 2 - 2 \cdot -2 \left(4 - 4\right) + 1 - 1

MathBot Answer:

−3+0⋅1+2−2⋅−2(4−4)+1−1=−1-3 + 0 \cdot 1 + 2 - 2 \cdot -2 \left(4 - 4\right) + 1 - 1 = -1

−3+0⋅1+2−2⋅−2(4−4)+1−1=−3+0+2−2⋅−2(4−4)+1−1=−3+2−2⋅−2(4−4)+1−1=−1−2⋅−2(4−4)+1−1=−1−−4(4−4)+1−1=−1−−4⋅0+1−1=−1−0+1−1=−1+1−1=0−1=−1\begin{aligned}-3 + 0 \cdot 1 + 2 - 2 \cdot -2 \left(4 - 4\right) + 1 - 1&=-3 + 0 + 2 - 2 \cdot -2 \left(4 - 4\right) + 1 - 1\\&=-3 + 2 - 2 \cdot -2 \left(4 - 4\right) + 1 - 1\\&=-1 - 2 \cdot -2 \left(4 - 4\right) + 1 - 1\\&=-1 - -4 \left(4 - 4\right) + 1 - 1\\&=-1 - -4 \cdot 0 + 1 - 1\\&=-1 - 0 + 1 - 1\\&=-1 + 1 - 1\\&=0 - 1\\&=-1\end{aligned}

+ Submit Question