−7−{−3+2+[−5−2+(1−3−4)]+7−1}=

asked by guest
on Apr 06, 2025 at 1:36 pm



You asked:

Evaluate the expression: 7(3+2+52+134+71)-7 - \left(-3 + 2 + -5 - 2 + 1 - 3 - 4 + 7 - 1\right)

MathBot Answer:

7(3+2+52+134+71)=1-7 - \left(-3 + 2 + -5 - 2 + 1 - 3 - 4 + 7 - 1\right) = 1


7(3+2+52+134+71)=7(1+52+134+71)=7(1+7+134+71)=7(1+7+24+71)=7(1+7+6+71)=7(1+13+71)=7(14+71)=7(71)=78=1\begin{aligned}-7 - \left(-3 + 2 + -5 - 2 + 1 - 3 - 4 + 7 - 1\right)&=-7 - \left(-1 + -5 - 2 + 1 - 3 - 4 + 7 - 1\right)\\&=-7 - \left(-1 + -7 + 1 - 3 - 4 + 7 - 1\right)\\&=-7 - \left(-1 + -7 + -2 - 4 + 7 - 1\right)\\&=-7 - \left(-1 + -7 + -6 + 7 - 1\right)\\&=-7 - \left(-1 + -13 + 7 - 1\right)\\&=-7 - \left(-14 + 7 - 1\right)\\&=-7 - \left(-7 - 1\right)\\&=-7 - -8\\&=1\end{aligned}