(6ab+4b)÷ (-1/2b)
For what value of 'k' the points ( -k + 1, 2k), (k, 2 - 2k) and ( - 4 - k, 6 - 2k) are collinear.
x+3=4x-1
5a-11
=4
4g=12
4.088 / 280
negative 3 over 7y to the power of negative 4
−x^3+2x^2−5x+5≤0
x to the power of negative three over y to the power of negative 5
5 over x to the power of 3 times y to the power of negative 4
