−x^3+2x^2−5x+5≤0

asked by guest
on Mar 24, 2025 at 7:52 pm



You asked:

Solve the inequality −x3+2x2−5x+5≤0 -{x}^{3} + 2 {x}^{2} - 5 x + 5 \le 0 for the variable xx.

MathBot Answer:

x≥−11⋅23361+310053+23+22361+3100536x \geq - \frac{11 \cdot \sqrt[3]{2}}{3 \sqrt[3]{61 + 3 \sqrt{1005}}} + \frac{2}{3} + \frac{2^{\frac{2}{3}} \sqrt[3]{61 + 3 \sqrt{1005}}}{6}

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