(6ab+4b)÷ (-1/2b)
asked by guest on Mar 24, 2025 at 8:12 pm
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MathBot Answer:
6ab+4b−12b=−2b(6ab+4b)\displaystyle \frac{6 a b + 4 b}{\frac{-1}{2 b}} = - 2 b \left(6 a b + 4 b\right) 2b−16ab+4b=−2b(6ab+4b)
6ab+4b−12b=−12b2a−8b2\frac{6 a b + 4 b}{\frac{-1}{2 b}} = - 12 b^{2} a - 8 b^{2}2b−16ab+4b=−12b2a−8b2
6ab+4b−12b=−4b2⋅(3a+2)\frac{6 a b + 4 b}{\frac{-1}{2 b}} = - 4 b^{2} \cdot \left(3 a + 2\right)2b−16ab+4b=−4b2⋅(3a+2)