(2**5+2**8)**5*2**-5
270/x-4=54
x - 5y = 10
2x - 5y = 40
(5/7 + 2/3) = 29/21
I+V = VI
((n+1)/(n^2+3n+1))-((n)/(n^2+n-1))
2p^2-4px+5pj=3x^2+x-8 if the products of the roots equals twice the sum.
(5/7+2/3) =
((n+1)/(n^2+n-1))-((n)/(n^2+n-1))
