(x-2)(x-1)
asked by guest on Apr 06, 2025 at 12:50 pm
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MathBot Answer:
(x−2)(x−1)=(x−2)(x−1)\displaystyle \left(x - 2\right) \left(x - 1\right) = \left(x - 2\right) \left(x - 1\right) (x−2)(x−1)=(x−2)(x−1)
(x−2)(x−1)=x2−3x+2\left(x - 2\right) \left(x - 1\right) = x^{2} - 3 x + 2(x−2)(x−1)=x2−3x+2