2x + 4y = 6

3x sin(30) - 2y = 12

asked by guest
on Apr 06, 2025 at 12:49 pm



You asked:

Solve the system of equations:2x+4y=63xsin⁡(30)−2y=12\begin{aligned}2 x + 4 y &= 6\\3 x \sin\left( 30 \right) - 2 y &= 12\end{aligned}

MathBot Answer:

The system of equations has one solution.x=−2⋅(12−9sin⁡(30))−2−6sin⁡(30)+3x = - \frac{2 \cdot \left(12 - 9 \sin{\left(30 \right)}\right)}{-2 - 6 \sin{\left(30 \right)}} + 3 y=12−9sin⁡(30)−2−6sin⁡(30)y = \frac{12 - 9 \sin{\left(30 \right)}}{-2 - 6 \sin{\left(30 \right)}}
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