√(16^3 )=16^(2/3)
lim(x,y)->(0,0) sen(x-y)/(x-y)
lim x,y (0,0) = sen(x-y)/(x-y)
5x/2 =3x+5
(-10+3\sqrt{7})+(3+12\sqrt{7})
√(〖16〗^3 )=〖16〗^□(2/3)
1 - x^2 - (3x+1)/2 = -(x^2)/4 + 5x - (3x^2)/4
x+2/x-3 =2
4x−2\frac{4}{x-2}x−24 - x2x−4\frac{x}{2x-4}2x−4x = 73x−6\frac{7}{3x-6}3x−67
4x−2\frac{4}{x-2}x−24 - x2x(x−2)\frac{x}{2x(x-2)}2x(x−2)x = 73x(x−2)\frac{7}{3x(x-2)}3x(x−2)7
