(1/2)log $\sqrt{8}$
x^2+4x
((-7/4)^2 - 3)/(2-7/4) = 1/4
10x^2 - 6 = 9x
1/2log $\sqrt{8}$
construct an angle whose measure is half of a straight angle and write the name
grafh of y=x
3x = 9x^2 - 10
\lim _{x\to 3}\left(\frac{\sqrt{x-2}-1}{\:\sqrt{x+4}-\sqrt{7}}\right)
x:(25-x)=3:7; Solve for x