(3𝑥^2 + 𝑦)𝑑𝑥 +(𝑥^2𝑦 −𝑥)𝑑𝑦 = 0

asked by guest
on Apr 04, 2025 at 5:06 pm



You asked:

Investigate the equation: (3x2+y)⋅dx+(x2y−x)⋅dy=0\left(3 {x}^{2} + y\right) \cdot d x + \left({x}^{2} y - x\right) \cdot d y = 0.

+ Submit Question