(5/3)^-5*(5/3)^11=(5/3)^(8*x)
Find the value of x
log(0.13)
1+4+7+10+..... +x=287 Find x
(5/3)^-5*(5/3)^-11=(5/3)^(8*x)
CALCULATE THE VOLUME FOR THE FOLLOWING CHANGES IN TEMPERATURE, TEN LITERS OF AIR IS HEATED FROM 300K TO 600K
590871
2725594
2012190
605079
5451188
4024380
22975516
express
the
following
ratios
in
their
simplest
(5/3)^-5*(5/3)^-11=(5/3)^8*x
(5/3)^-5*(5/3)^-11=(5/3)^8x
