If the 1st and 10th terms of an arithmetic sequence are 3 and 30, respectively, find the 40th term of the sequence.
1+3x/4=y
x^2+4x+2x+8
1649676
36814420
30324376
5608252
6749810
9915932
257723214634662
159534513318297
29742÷5205053
759139÷760845
solve (7.1 × 10–15) × (2 × 103)
257723214634662.
12 / 6 * 8 +14
73.92 /5.6
m^2-9m+8
.21794
.80088089
14634662.13318297
