4!/(2!*3!)

asked by guest
on Apr 06, 2025 at 6:12 pm



You asked:

Evaluate the expression: 4!2!⋅3!\frac{4!}{2! \cdot 3!}

MathBot Answer:

4!2!⋅3!=2\frac{4!}{2! \cdot 3!} = 2

4!2!⋅3!=4!⋅12!⋅3!=24⋅12!⋅3!=24⋅12⋅3!=24⋅12⋅6=2412=2\begin{aligned}\frac{4!}{2! \cdot 3!}&=4! \cdot \frac{1}{2! \cdot 3!}\\&=24 \cdot \frac{1}{2! \cdot 3!}\\&=24 \cdot \frac{1}{2 \cdot 3!}\\&=24 \cdot \frac{1}{2 \cdot 6}\\&=\frac{24}{12}\\&=2\end{aligned}

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