$$\sum_{a}^{b}{$i^{8}$ }$$
5m-7n+3n-4m+2+2m-3mm-5
$(x+y)^{2}$ =4
10(-1)
how to get the number -12 with the number 4,7,8,2,5
x
-2x+4
(0.36 Log^2 0.36)-(0.64 Log^2 0.64)
f(x)=log(x+1)
3|\frac{2+2x}{x-2}|-5=10
