log3(x)-log9(x)=1
SIMPLIFY 2^2-3^2-4^2
5*5
$x^{2}$ -8x-33=0
a^2+3a+5a+15
(x)= -x² + 4x + 20
5–(7–10)–10–(5–2)
$x^{3}$ - $6x^{2}$ + 9x = 0
$x^{3}$ - $6x^{2}$ + $9^{x}$ = 0
=
\frac{
(1,28\cdot 10^{12}) \cdot e^{0,087t}
}{
(10)^{10}e^{2 \cdot
0,087t} - 4,49\cdot 10^{6} \cdot e^{0,087t} ...
