What is 16^(3/4)?
Simplify (z^(5/4)) * (z^(1/4))
1+1=
Evaluate 27^(2/3)
6y-5=-3(2y+1)
Evaluate 125^(2/3).
$\frac{x^2 + 8x + 16\}{x^2 - 16\}$ ÷ $\frac{x^2 - 3x - 28\}{x - 7\}$
Evaluate 32^(3/5).
Solve for x: x^(2/3) = 4.
a=0.122b+0.992c
(a/2.432)=0.992b-0.122c
5905.49=0.955b-0.295c
d=0.295b+0.955c
solve the equation system