6y-5=-3(2y+1)
You asked:
Solve the equation \(6 y - 5 = -\left( 3 \cdot \left(2 y + 1\right) \right)\) for the variable \(y\).
MathBot Answer:
The solution is: \[y = \frac{1}{6} = 0.1\overline{6}\]
\[\begin{aligned}6 y - 5 &= - 6 y - 3\\12 y &= 2\\y &= \frac{1}{6}\end{aligned}\]