Math Problem Solver

f(1+3–√3)

f(1+3–√3)=(1+3–√3)3−3(1+3–√3)2+2(1+3–√3)−1

20=9 80=x find x

f(1+3–√3)=(1+3–√3)3−3(1+3–√3)2+2(1+3–√3)−1

(1+3–√3)3−3(1+3–√3)2+2(1+3–√3)−1

2(x+3)=x-4

13(-2-11n)=-26+2n

∫

0

2π

​

∫

π/4

π

​

∫

0

2

​

ρ

4

1

​

ρ

2

sinϕdρdϕdθ.

Express using positive exponents. Then simplify.

5-2

25

-25

8-11(k-8)=30-5k