f(1+3–√3)=(1+3–√3)3−3(1+3–√3)2+2(1+3–√3)−1
You asked:
Investigate the relation \(f\left( 1 + 3 - \sqrt{3} \right) = \left(1 + 3 - \sqrt{3}\right) \cdot 3 - 3 \cdot \left(1 + 3 - \sqrt{3}\right) \cdot 2 + 2 \cdot \left(1 + 3 - \sqrt{3}\right) - 1\).