x²-6x-27=0
if the two roots of the equation:kx $a^{b}$ 2-8x+16=0 are complex and non-real,then
x^2,12=75625
7/8 plus 1/6 divided by 2/9
h(x)=1.5x
determine h-1(x) algebrically
4m²-1
(-4i)(-6i)=
-2(a+4)=18
4x²-15x+35=9x+8
7/8+1/6 / 2/9