((2*10^9)(2*10^9+1))/2

asked by guest
on Apr 10, 2025 at 4:25 am



You asked:

Evaluate the expression: 2⋅109(2⋅109+1)2\frac{2 \cdot {10}^{9} \left(2 \cdot {10}^{9} + 1\right)}{2}

MathBot Answer:

2⋅109(2⋅109+1)2=2000000001000000000\frac{2 \cdot {10}^{9} \left(2 \cdot {10}^{9} + 1\right)}{2} = 2000000001000000000

2⋅109(2⋅109+1)2=2⋅1000000000(2⋅109+1)2=2000000000(2⋅109+1)2=2000000000(2⋅1000000000+1)2=2000000000(2000000000+1)2=2000000000⋅20000000012=40000000020000000002=2000000001000000000\begin{aligned}\frac{2 \cdot {10}^{9} \left(2 \cdot {10}^{9} + 1\right)}{2}&=\frac{2 \cdot 1000000000 \left(2 \cdot {10}^{9} + 1\right)}{2}\\&=\frac{2000000000 \left(2 \cdot {10}^{9} + 1\right)}{2}\\&=\frac{2000000000 \left(2 \cdot 1000000000 + 1\right)}{2}\\&=\frac{2000000000 \left(2000000000 + 1\right)}{2}\\&=\frac{2000000000 \cdot 2000000001}{2}\\&=\frac{4000000002000000000}{2}\\&=2000000001000000000\end{aligned}

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