[matematik]\displaystyle{ \prod_{k=3}^\infty \cos\left(\frac\pi k\right) = 0.1149420448\dots. }[/matematik]
2^(n)(An^2+Bn+C)-4{2^(n-1)[A(n-1)^2+B(n-1)+C]}+4{2^(n-2)[A(n-2)^2+B(n-2)+C]} -(n+1)2^n = 0
2^n(An^2+Bn+C)-4{2^(n-1)[A(n-1)^2+B(n-1)+C]}+4{2^(n-2)[A(n-2)^2+B(n-2)+C]} -(n+1)2^n = 0
q^2+7q+6=0
x+(70/x^2)=7.7
199+165+137+367+455
325q^2-2125q-11250=0
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