2.9cos 17degrees
asked by guest on Apr 06, 2025 at 9:54 am
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MathBot Answer:
2.9cos(17∘)=29cos(17π180)10\displaystyle 2.9 \cos\left( 17^{\circ} \right) = \frac{29 \cos{\left(\frac{17 \pi}{180} \right)}}{10} 2.9cos(17∘)=1029cos(18017π)
2.9cos(17∘)=29cos(17deg)102.9 \cos\left( 17^{\circ} \right) = \frac{29 \cos{\left(17 \text{deg} \right)}}{10}2.9cos(17∘)=1029cos(17deg)