tanA\cotA
tanA/
-18-6k=6(1+3k)
x^2+1/x^2+4 + 3/x^2+4
3x=5(x+3)-3
5n+34=-2(1-7n)
a+b
4(x-1)-9(x-2)=0
2(x+5)+3(x-4)=17
2(3x-4)=3x-1
