x^2+1/x^2+4 + 3/x^2+4
asked by guest on Apr 04, 2025 at 5:43 pm
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x2+1x2+4+3x2+4=x2+8+4x2\displaystyle {x}^{2} + \frac{1}{{x}^{2}} + 4 + \frac{3}{{x}^{2}} + 4 = x^{2} + 8 + \frac{4}{x^{2}} x2+x21+4+x23+4=x2+8+x24
x2+1x2+4+3x2+4=x4+8x2+4x2{x}^{2} + \frac{1}{{x}^{2}} + 4 + \frac{3}{{x}^{2}} + 4 = \frac{x^{4} + 8 x^{2} + 4}{x^{2}}x2+x21+4+x23+4=x2x4+8x2+4