xy - x^2 = 4
4x^2 - 4xy = 16 - 2y^2
(m^3/m^2)2/5
X=3(X-5.5)
x$^{2}$-5x+2=0
What must be taken away from the product (x
2
−3x)(x
3
+4x
−1) to get 2x
5
+x
−3x ?
(-5x^2+4-2x^3-6x)\div (x-1)
X=3X-5.5
x²+5xx+7=9
3 $\sqrt{\Box}$ 81 $a_{b}$ 3
y
=
(
x
−
+
1
)
12