(-5x^2+4-2x^3-6x)\div (x-1)

asked by guest
on Oct 24, 2024 at 12:22 am



You asked:

Evaluate the expression: \(\frac{-\left( 5 \cdot {x}^{2} \right) + 4 - 2 \cdot {x}^{3} - 6 x}{x - 1}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{-\left( 5 \cdot {x}^{2} \right) + 4 - 2 \cdot {x}^{3} - 6 x}{x - 1} = \frac{- 2 x^{3} - 5 x^{2} - 6 x + 4}{x - 1} \)


Expanded

\[\frac{-\left( 5 \cdot {x}^{2} \right) + 4 - 2 \cdot {x}^{3} - 6 x}{x - 1} = - \frac{2 x^{3}}{x - 1} - \frac{5 x^{2}}{x - 1} - \frac{6 x}{x - 1} + \frac{4}{x - 1}\]


Factored

\[\frac{-\left( 5 \cdot {x}^{2} \right) + 4 - 2 \cdot {x}^{3} - 6 x}{x - 1} = - \frac{2 x^{3} + 5 x^{2} + 6 x - 4}{x - 1}\]