16 divided by 9 cube root
14-11* $\frac{\8}{\5}$
16 dived by 9 cube rootes
-4+2+-3+7
9÷3(3)=
$$\sum_{a}^{b}{C}$$ $$\sum_{a}^{b}{C}$$ $$\sum_{a}^{b}{C}$$
findi the value of y in the equation below, give your answer as a decimal
y-5.3=14.2
13-11* $\frac{\7}{\5}$
(x-y)squared=16 divides by 9
6x+5y+3=0
13-11* $\frac{\8}{\5}$
