Find that smallest number which when divided by 4, 6, 8, 12, and 16 leaves 2 as the remainder in each case.
Find that smallest number which when divided by 4, 6, 8, 12, and 16 leaves 2 as the remainder in each case... Read more at: https:...
1/3rd of 100
1/2x+1=x
simplify $\pi$
y^2=4x
y^2=4x+4
factorize completely 12b(x-3y)+24c(x-3y)
factorize completely 50a-200ab
factorize 50a-200ab
