Math Problem Solver

The graph of the equation ${y}^{2} = 4 x$ is a parabola.

The coordinates of its vertex are: $\left(0, 0\right)$

The coordinates of its focus are: $\left(1, 0\right)$

The directrix has equation: $x + 1 = 0$.

The parabola has parameterization: $$\begin{aligned}x\left(\theta\right) &= \frac{\theta^{2}}{4}\\y\left(\theta\right) &= \theta\end{aligned}$$