Write x^2-6x+14 in the form (x+a)^2+b where a and b are integers.
b+22/25=7b/5
b+2a
$$\int_{\1}^{\2}1/(\x^2+6x+5x) dx$$
9c^2 + 1/9c^2 -2 + 9c - 1/c
16s2 + 1/16s² - 2 + 16s - 1/s
$x^{2}$ - 5$x$ +6
round 61 to the nearest ten
find $$\int_{\1}^{\2}(\1) d/x^2+6x+5x$$
2x*3xy
9 1/2+6 1/6
