Math Problem Solver

$$\frac{1}{3} + \frac{1}{9} = \frac{4}{9} = 0.\overline{4}$$

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of $\frac{1}{3}$ and $\frac{1}{9}$ is $9$. $$\begin{aligned} \frac{1}{3} + \frac{1}{9} &= \frac{1 \cdot 3}{3 \cdot 3} + \frac{1 \cdot 1}{9 \cdot 1} \\ &= \frac{3 + 1}{9} \\ &= \frac{4}{9} \end{aligned}$$