2p²+5p-4=0
r²+5r+2=0
-7+(-5-(-7+11-9)-4+3)-2+9=
4x^{\frac{-1}{2}}\left(x^{\frac{5}{2}}-x^{\frac{-3}{2}}\right)
Find the value of the real number 𝜆 in the case when √3 + 𝑖𝜆 is real. 1 + 𝑖√3
5b²+b-2=0
-4m²-4m+5=0
-2x²-x-1=0
$\frac{1}{x+1}$ -x+ $\frac{3}{2}$ -1=0
30x-18>252, answer with least or most