sin(5 π\piπ -x)+cos(-11 π\piπ+x)-sin(3 π\piπ -x)+sin(7 π\piπ +x)
asked by guest on Mar 29, 2025 at 3:08 am
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MathBot Answer:
sin(5π−x)+cos(−(11π)+x)−sin(3π−x)+sin(7π+x)=−sin(x)−cos(x)\sin\left( 5 \pi - x \right) + \cos\left( -\left( 11 \pi \right) + x \right) - \sin\left( 3 \pi - x \right) + \sin\left( 7 \pi + x \right) = - \sin{\left(x \right)} - \cos{\left(x \right)}sin(5π−x)+cos(−(11π)+x)−sin(3π−x)+sin(7π+x)=−sin(x)−cos(x)